0,1x^2-0,3x+0,125=0

Solution for 0,1x^2-0,3x+0,125=0 equation:

0.1x^2-0.3x+0.125=0

a = 0.1; b = -0.3; c = +0.125;
Δ = b2-4ac
Δ = -0.32-4·0.1·0.125
Δ = 0.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.3)-\sqrt{0.04}}{2*0.1}=\frac{0.3-\sqrt{0.04}}{0.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.3)+\sqrt{0.04}}{2*0.1}=\frac{0.3+\sqrt{0.04}}{0.2}
$